ソースを参照

Merge branch 'master' of hartley.uberspace.de:christian/ana-lecture

master
JosuaKugler 5年前
コミット
daa889bfbe
1個のファイルの変更11行の追加11行の削除
  1. +11
    -11
      lecture.cls

+ 11
- 11
lecture.cls ファイルの表示

@@ -25,6 +25,7 @@
\RequirePackage{bookmark}
\RequirePackage{wasysym}
\RequirePackage{environ}
\RequirePackage{stackrel}

\usetikzlibrary{quotes, angles}

@@ -134,8 +135,8 @@

% better stackrel
\let\oldstackrel\stackrel
\renewcommand{\stackrel}[2]{%
\oldstackrel{\mathclap{#1}}{#2}
\renewcommand{\stackrel}[3][]{%
\oldstackrel[\mathclap{#1}]{\mathclap{#2}}{#3}
}%

% integral d sign
@@ -183,6 +184,7 @@
\box_new:N \l_tmp_box
\dim_new:N \l_tmp_dim_a
\dim_new:N \l_tmp_dim_b
\dim_new:N \l_tmp_dim_c
\dim_new:N \l_tmp_dim_needed

% function to insert padding according to widest stackrel
@@ -190,7 +192,7 @@
{
\tl_set:Nn \l__lec_text_tl { #1 }
% get all stackrels in this align environment
\regex_extract_all:nnN { \c{stackrel}{(.*?)}{(.*?)} } { #1 } \l_lec_stackrels_seq
\regex_extract_all:nnN { \c{stackrel}(\[.*?\])?{(.*?)}{(.*?)} } { #1 } \l_lec_stackrels_seq
% get number of stackrels
\int_set:Nn \l_stackrel_count_int { \seq_count:N \l_lec_stackrels_seq }
\int_set:Nn \l_idx_int { 1 }
@@ -201,30 +203,28 @@
% calculate width of text
\hbox_set:Nn \l_tmp_box {$\seq_item:Nn \l_lec_stackrels_seq { \l_idx_int + 1 }$}
\dim_set:Nn \l_tmp_dim_a {\box_wd:N \l_tmp_box}
% calculate width of relation symbol
\hbox_set:Nn \l_tmp_box {$\seq_item:Nn \l_lec_stackrels_seq { \l_idx_int + 2 }$}
\dim_set:Nn \l_tmp_dim_c {\box_wd:N \l_tmp_box}
\dim_set:Nn \l_tmp_dim_a {\dim_max:nn{ \l_tmp_dim_c} {\l_tmp_dim_a}}
% calculate width of relation symbol
\hbox_set:Nn \l_tmp_box {$\seq_item:Nn \l_lec_stackrels_seq { \l_idx_int + 3 }$}
\dim_set:Nn \l_tmp_dim_b {\box_wd:N \l_tmp_box}
% check if 0.5*(a-b) > minimum padding, if yes updated minimum padding
\dim_compare:nNnTF
{ 1pt * \dim_ratio:nn { \l_tmp_dim_a - \l_tmp_dim_b } { 2pt } } > { \l_tmp_dim_needed }
{ \dim_set:Nn \l_tmp_dim_needed { 1pt * \dim_ratio:nn { \l_tmp_dim_a - \l_tmp_dim_b } { 2pt } } }
{ }
\quad
% increment list index by three, as every stackrel produces three list entries
\int_incr:N \l_idx_int
\int_incr:N \l_idx_int
\int_incr:N \l_idx_int
\int_incr:N \l_idx_int
}
% replace all relations with align characters (&) and add the needed padding
\regex_replace_all:nnN
{ (\c{iff}&|&\c{iff}|\c{impliedby}&|&\c{impliedby}|\c{implies}&|&\c{implies}|\c{approx}&|&\c{approx}|\c{equiv}&|&\c{equiv}|=&|&=|\c{le}&|&\c{le}|\c{ge}&|&\c{ge}|&\c{stackrel}{.*?}{.*?}|\c{stackrel}{.*?}{.*?}&|&\c{neq}|\c{neq}&|>&|&>|<&|&<) }
{ (\c{iff}&|&\c{iff}|\c{impliedby}&|&\c{impliedby}|\c{implies}&|&\c{implies}|\c{approx}&|&\c{approx}|\c{equiv}&|&\c{equiv}|=&|&=|\c{le}&|&\c{le}|\c{ge}&|&\c{ge}|&\c{stackrel}(\[.*?\])?{.*?}{.*?}|\c{stackrel}(\[.*?\])?{.*?}{.*?}&|&\c{neq}|\c{neq}&|>&|&>|<&|&<) }
{ \c{kern} \u{l_tmp_dim_needed} \1 \c{kern} \u{l_tmp_dim_needed} }
\l__lec_text_tl
% replace all parantheses with \left( \right)
%\regex_replace_all:nnN { \( } { \c{left}( } \l__lec_text_tl
%\regex_replace_all:nnN { \) } { \c{right}) } \l__lec_text_tl
%\regex_replace_all:nnN { \[ } { \c{left}[ } \l__lec_text_tl
%\regex_replace_all:nnN { \] } { \c{right}] } \l__lec_text_tl
\l__lec_text_tl
}
\cs_generate_variant:Nn \lec_insert_padding:n { V }


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