|
|
@@ -0,0 +1,194 @@ |
|
|
|
|
|
\documentclass{lecture} |
|
|
|
|
|
|
|
|
|
|
|
\begin{document} |
|
|
|
|
|
|
|
|
|
|
|
\section{Group schemes over a field} |
|
|
|
|
|
|
|
|
|
|
|
Let $k$ be a field and $S = \Spec k$. |
|
|
|
|
|
|
|
|
|
|
|
\begin{lemma} |
|
|
|
|
|
Let $G$ be a group scheme over $k$. Then $G \to \Spec k$ is separated. |
|
|
|
|
|
\end{lemma} |
|
|
|
|
|
|
|
|
|
|
|
\begin{proof} |
|
|
|
|
|
Let $\pi \colon G \to S$ the structure morphism. Then |
|
|
|
|
|
$\pi$ is separated if and only if $e\colon S \to G$ is a closed immersion. For |
|
|
|
|
|
any $x \in \mathrm{im}(e) \in G$, choose an affine open neighbourhood |
|
|
|
|
|
$x \in U = \Spec A \subseteq G$. |
|
|
|
|
|
Then $\pi|_{U} \circ e = \mathrm{id}_S$, hence the induced map |
|
|
|
|
|
$A \xrightarrow{\Gamma(e)} k$ has a section $\Gamma(\pi|_U)$ and is therefore |
|
|
|
|
|
surjective. Thus $e$ is a closed immersion. |
|
|
|
|
|
\end{proof} |
|
|
|
|
|
|
|
|
|
|
|
\begin{satz} |
|
|
|
|
|
Let $G$ be a group scheme locally of finite type over $k$. Then |
|
|
|
|
|
$G$ is smooth over $k$ if and only if $G$ is geometrically reduced. |
|
|
|
|
|
\end{satz} |
|
|
|
|
|
|
|
|
|
|
|
\begin{proof} |
|
|
|
|
|
The first direction is immediate, since smoothness is invariant under base change and |
|
|
|
|
|
smooth over a field implies reduced. |
|
|
|
|
|
Conversely, for any field extension $\ell / k$ by a prior result |
|
|
|
|
|
$G$ is smooth over $k$ if and only if $G$ is smooth over $\ell$. Thus |
|
|
|
|
|
we may assume $k = \bar k$. By \ref{idk} and \ref{idk}, we obtain |
|
|
|
|
|
$G_{\mathrm{sm}} \neq \emptyset$. By the transitive action |
|
|
|
|
|
of $G(k)$ on $G$, every closed point is smooth. Since |
|
|
|
|
|
\[ |
|
|
|
|
|
G_{(0)} = \{ g \in G \mid \mathrm{dim} \overline{\{g\}} = 0 \} |
|
|
|
|
|
\] is very dense in $G$ and $G_{\mathrm{sm}} \subseteq G$ is open, the result follows. |
|
|
|
|
|
\end{proof} |
|
|
|
|
|
|
|
|
|
|
|
\begin{lemma} |
|
|
|
|
|
Let $k$ be perfect and $G$ a group scheme locally of finite type over $k$. Then |
|
|
|
|
|
the induced reduced subscheme $G_{\mathrm{red}}$ is a subgroup scheme of $G$. |
|
|
|
|
|
\end{lemma} |
|
|
|
|
|
|
|
|
|
|
|
\begin{proof} |
|
|
|
|
|
Since $(-)_{\mathrm{red}}$ is a functor, we obtain |
|
|
|
|
|
$i\colon G_{\mathrm{red}} \to G_{\mathrm{red}}$ and |
|
|
|
|
|
$e\colon S \to G_{\mathrm{red}}$. By \ref{idk}, |
|
|
|
|
|
reduced is equivalent to geometrically reduced since $k$ is perfect. Thus |
|
|
|
|
|
$G_{\mathrm{red}} \times_k G_{\mathrm{red}}$ is reduced and we obtain |
|
|
|
|
|
\[ |
|
|
|
|
|
\begin{tikzcd} |
|
|
|
|
|
G x_k G \arrow{r}{m} & G \\ |
|
|
|
|
|
G_{\mathrm{red}} \times_k G_{\mathrm{red}} \arrow{u} |
|
|
|
|
|
\arrow[dashed]{r} & G_{\mathrm{red}} \arrow{u} |
|
|
|
|
|
\end{tikzcd} |
|
|
|
|
|
.\] |
|
|
|
|
|
\end{proof} |
|
|
|
|
|
|
|
|
|
|
|
\begin{korollar} |
|
|
|
|
|
If $k$ is perfect and $G$ a group scheme locally of finite type over $k$. Then |
|
|
|
|
|
$G_{\mathrm{red}}$ is smooth over $k$. |
|
|
|
|
|
\end{korollar} |
|
|
|
|
|
|
|
|
|
|
|
\begin{lemma} |
|
|
|
|
|
Let $G$ be locally of finite type over $k$. Then $G$ is geometrically irreducible |
|
|
|
|
|
if (and only if) $G$ is connected. |
|
|
|
|
|
\end{lemma} |
|
|
|
|
|
|
|
|
|
|
|
\begin{proof} |
|
|
|
|
|
Since $G(k) \neq \emptyset$, we have a morphism |
|
|
|
|
|
$\Spec k \to G$ and $\Spec k$ is geometrically connected. Thus $G$ is geometrically connected. |
|
|
|
|
|
We may therefore assume $k = \bar k$. Since the statement is purely topological, we may |
|
|
|
|
|
further assume that $G$ is reduced and thus smooth over $k$. Hence |
|
|
|
|
|
$G$ is regular by \ref{idk}, in particular for every $g \in G$ the local ring |
|
|
|
|
|
$\mathcal{O}_{G,g}$ is regular and hence an integral domain. Since $G$ is locally noetherian |
|
|
|
|
|
and connected, the claim follows. |
|
|
|
|
|
\end{proof} |
|
|
|
|
|
|
|
|
|
|
|
\begin{definition} |
|
|
|
|
|
An \emph{abelian variety} over $k$ is a connected, geometrically reduced |
|
|
|
|
|
and proper $k$-group scheme. |
|
|
|
|
|
\end{definition} |
|
|
|
|
|
|
|
|
|
|
|
\begin{bem} |
|
|
|
|
|
Abelian varieties are smooth and geometrically integral. |
|
|
|
|
|
\end{bem} |
|
|
|
|
|
|
|
|
|
|
|
\begin{bsp} |
|
|
|
|
|
Elliptic curves are abelian varieties of dimension $1$. |
|
|
|
|
|
\end{bsp} |
|
|
|
|
|
|
|
|
|
|
|
The goal is now to show that abelian varieties are commutative group schemes. |
|
|
|
|
|
|
|
|
|
|
|
\begin{lemma} |
|
|
|
|
|
Let $X$ be a proper, geometrically connected and geometrically reduced $k$-scheme and |
|
|
|
|
|
$Y$ an affine $k$-scheme. Then every morphism $X \xrightarrow{f} Y$ factors over a |
|
|
|
|
|
$k$-valued point of $Y$. |
|
|
|
|
|
\label{lemma:constant-of-proper-conn-irred-affine} |
|
|
|
|
|
\end{lemma} |
|
|
|
|
|
|
|
|
|
|
|
\begin{proof} |
|
|
|
|
|
By the Liouville theorem for schemes, the global |
|
|
|
|
|
sections of $\mathcal{O}_{X_{\bar k}}$ is $\bar k$. Since |
|
|
|
|
|
$k \to \bar k$ is flat, we obtain |
|
|
|
|
|
\[ |
|
|
|
|
|
\Gamma(X, \mathcal{O}_X) \otimes_k \bar k |
|
|
|
|
|
\xlongrightarrow{\simeq} \Gamma(X_{\bar k}, \mathcal{O}_{X_{\bar k}}) |
|
|
|
|
|
.\] Since $k \to \bar k$ is even faithfully flat, we obtain |
|
|
|
|
|
$\Gamma(X, \mathcal{O}_X) \simeq k$. |
|
|
|
|
|
|
|
|
|
|
|
Choose an embedding $Y \hookrightarrow \mathbb{A}_k^{(I)}$. Then a |
|
|
|
|
|
morphism $f\colon X \to Y$ is equivalent to a morphism |
|
|
|
|
|
$X \xrightarrow{f} Y \hookrightarrow \mathbb{A}_k^{(I)}$, which is equivalent |
|
|
|
|
|
to the datum of a family of $e_i \in \Gamma(X, \mathcal{O}_X)$ which |
|
|
|
|
|
corresponds to a morphism |
|
|
|
|
|
$\Spec k \xrightarrow{e} \mathbb{A}_k^{(I)}$. Thus by construction we obtain |
|
|
|
|
|
a factorisation |
|
|
|
|
|
\[ |
|
|
|
|
|
\begin{tikzcd} |
|
|
|
|
|
X \arrow{r}{f} \arrow[dashed]{d} & Y \arrow{r} & \mathbb{A}^{(I)} \\ |
|
|
|
|
|
\Spec k \arrow{rru} |
|
|
|
|
|
\end{tikzcd} |
|
|
|
|
|
\] where the dashed arrow is induced from the isomorphism $\Gamma(X, \mathcal{O}_X) \simeq k$. |
|
|
|
|
|
\end{proof} |
|
|
|
|
|
|
|
|
|
|
|
\begin{lemma}[Rigidity] |
|
|
|
|
|
Let $X$ be a geometrically reduced, geometrically connected and proper $k$-scheme |
|
|
|
|
|
with $X(k) \neq \emptyset$. Let further $Y$ be an integral scheme over $k$, $Z$ |
|
|
|
|
|
be a separated $k$-scheme and $f\colon X \times_k Y \to Z$ a morphism such that |
|
|
|
|
|
there exists $y \in Y(k)$ such that |
|
|
|
|
|
$f|_{X_{y}}$ factors via a $k$-point $z \in Z(k)$. Then |
|
|
|
|
|
$f$ factors via $\mathrm{pr}_2$. |
|
|
|
|
|
\label{lemma:rigidity} |
|
|
|
|
|
\end{lemma} |
|
|
|
|
|
|
|
|
|
|
|
\begin{proof} |
|
|
|
|
|
Consider the composition |
|
|
|
|
|
\[ |
|
|
|
|
|
g\colon X \times_k Y \xrightarrow{pr_2} Y \simeq \Spec k \times_k Y |
|
|
|
|
|
\xrightarrow{(x_0, \mathrm{id})} X \times_k Y \xrightarrow{f} Z |
|
|
|
|
|
\] where $x_0$ is an arbitrarily chosen $k$-rational point of $X$. |
|
|
|
|
|
It remains to show that $f = g$. Choose an open affine |
|
|
|
|
|
neighbourhood $z \in U \subseteq Z$. Then |
|
|
|
|
|
$X_y = \mathrm{pr}_2^{-1}(y) \subseteq f^{-1}(U)$. Since |
|
|
|
|
|
$X$ is proper, $\mathrm{pr}_2$ is a closed map. Thus there |
|
|
|
|
|
exists a $y \in V \subseteq Y$ open |
|
|
|
|
|
with $\mathrm{pr}_2^{-1}(V) \subseteq f^{-1}(U)$. For |
|
|
|
|
|
any $y' \in V$, we obtain |
|
|
|
|
|
\[ |
|
|
|
|
|
\begin{tikzcd} |
|
|
|
|
|
X \times_k Y \arrow{r}{f} & Z \\ |
|
|
|
|
|
X_{y'} \arrow[dashed, swap]{d}{\alpha(y')} |
|
|
|
|
|
\arrow[hookrightarrow]{u} \arrow[dashed]{r} & U \arrow[hookrightarrow]{u} \\ |
|
|
|
|
|
U \times_k \kappa(y') \arrow{ur} |
|
|
|
|
|
\end{tikzcd} |
|
|
|
|
|
.\] By \ref{lemma:constant-of-proper-conn-irred-affine}, the morphism |
|
|
|
|
|
$\alpha(y')$ factors over a $\kappa(y')$-valued point. Thus |
|
|
|
|
|
$f$ and $g$ agree on the dense open subset $X \times_k V$. By reduced-to-separated, |
|
|
|
|
|
the result follows. |
|
|
|
|
|
\end{proof} |
|
|
|
|
|
|
|
|
|
|
|
\begin{korollar} |
|
|
|
|
|
Let $A$ and $B$ be abelian varieties over $k$ |
|
|
|
|
|
and $f$ a morphism of $k$-schemes $A \to B$. If under the induced |
|
|
|
|
|
map $f(k)\colon A(k) \to B(k)$ the identity $e_A$ is mapped to $e_B$. |
|
|
|
|
|
\label{cor:av-group-homs} |
|
|
|
|
|
\end{korollar} |
|
|
|
|
|
|
|
|
|
|
|
\begin{proof} |
|
|
|
|
|
Consider the composition |
|
|
|
|
|
\[ |
|
|
|
|
|
g\colon A \times_k A \xrightarrow{(f \circ m_A) \times (i_B \circ m_A \circ (f \times f))} |
|
|
|
|
|
B \times_k B |
|
|
|
|
|
\xrightarrow{m_B} |
|
|
|
|
|
B |
|
|
|
|
|
.\] It remains to show that the image of $g$ is precisely $\{e_B\} $. By |
|
|
|
|
|
assumption $f(e_A) = e_B$ and thus |
|
|
|
|
|
\[ |
|
|
|
|
|
g(\{e_A\} \times_k A) = \{ e_B\} = g(A \times_k \{e_A\}) |
|
|
|
|
|
.\] By repeated application of \ref{lemma:rigidity}, $g$ factors |
|
|
|
|
|
via $\mathrm{pr}_1$ and $\mathrm{pr}_2$. Thus $g$ is constant and $e_B$ is in the image. |
|
|
|
|
|
\end{proof} |
|
|
|
|
|
|
|
|
|
|
|
\begin{korollar} |
|
|
|
|
|
Every abelian variety is commutative. |
|
|
|
|
|
\end{korollar} |
|
|
|
|
|
|
|
|
|
|
|
\begin{proof} |
|
|
|
|
|
Apply \ref{cor:av-group-homs} on $i\colon A \to A$. |
|
|
|
|
|
\end{proof} |
|
|
|
|
|
|
|
|
|
|
|
\end{document} |