add lec4
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@@ -22,6 +22,7 @@ Christian Merten\\
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\input{lec01}
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\input{lec01}
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\input{lec02}
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\input{lec02}
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\input{lec03}
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\input{lec03}
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\input{lec04}
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\bibliographystyle{alpha}
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\bibliographystyle{alpha}
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\bibliography{refs}
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\bibliography{refs}
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@@ -0,0 +1,194 @@
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\documentclass{lecture}
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\begin{document}
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\section{Group schemes over a field}
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Let $k$ be a field and $S = \Spec k$.
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\begin{lemma}
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Let $G$ be a group scheme over $k$. Then $G \to \Spec k$ is separated.
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\end{lemma}
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\begin{proof}
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Let $\pi \colon G \to S$ the structure morphism. Then
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$\pi$ is separated if and only if $e\colon S \to G$ is a closed immersion. For
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any $x \in \mathrm{im}(e) \in G$, choose an affine open neighbourhood
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$x \in U = \Spec A \subseteq G$.
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Then $\pi|_{U} \circ e = \mathrm{id}_S$, hence the induced map
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$A \xrightarrow{\Gamma(e)} k$ has a section $\Gamma(\pi|_U)$ and is therefore
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surjective. Thus $e$ is a closed immersion.
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\end{proof}
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\begin{satz}
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Let $G$ be a group scheme locally of finite type over $k$. Then
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$G$ is smooth over $k$ if and only if $G$ is geometrically reduced.
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\end{satz}
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\begin{proof}
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The first direction is immediate, since smoothness is invariant under base change and
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smooth over a field implies reduced.
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Conversely, for any field extension $\ell / k$ by a prior result
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$G$ is smooth over $k$ if and only if $G$ is smooth over $\ell$. Thus
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we may assume $k = \bar k$. By \ref{idk} and \ref{idk}, we obtain
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$G_{\mathrm{sm}} \neq \emptyset$. By the transitive action
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of $G(k)$ on $G$, every closed point is smooth. Since
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\[
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G_{(0)} = \{ g \in G \mid \mathrm{dim} \overline{\{g\}} = 0 \}
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\] is very dense in $G$ and $G_{\mathrm{sm}} \subseteq G$ is open, the result follows.
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\end{proof}
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\begin{lemma}
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Let $k$ be perfect and $G$ a group scheme locally of finite type over $k$. Then
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the induced reduced subscheme $G_{\mathrm{red}}$ is a subgroup scheme of $G$.
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\end{lemma}
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\begin{proof}
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Since $(-)_{\mathrm{red}}$ is a functor, we obtain
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$i\colon G_{\mathrm{red}} \to G_{\mathrm{red}}$ and
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$e\colon S \to G_{\mathrm{red}}$. By \ref{idk},
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reduced is equivalent to geometrically reduced since $k$ is perfect. Thus
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$G_{\mathrm{red}} \times_k G_{\mathrm{red}}$ is reduced and we obtain
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\[
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\begin{tikzcd}
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G x_k G \arrow{r}{m} & G \\
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G_{\mathrm{red}} \times_k G_{\mathrm{red}} \arrow{u}
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\arrow[dashed]{r} & G_{\mathrm{red}} \arrow{u}
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\end{tikzcd}
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.\]
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\end{proof}
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\begin{korollar}
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If $k$ is perfect and $G$ a group scheme locally of finite type over $k$. Then
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$G_{\mathrm{red}}$ is smooth over $k$.
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\end{korollar}
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\begin{lemma}
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Let $G$ be locally of finite type over $k$. Then $G$ is geometrically irreducible
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if (and only if) $G$ is connected.
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\end{lemma}
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\begin{proof}
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Since $G(k) \neq \emptyset$, we have a morphism
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$\Spec k \to G$ and $\Spec k$ is geometrically connected. Thus $G$ is geometrically connected.
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We may therefore assume $k = \bar k$. Since the statement is purely topological, we may
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further assume that $G$ is reduced and thus smooth over $k$. Hence
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$G$ is regular by \ref{idk}, in particular for every $g \in G$ the local ring
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$\mathcal{O}_{G,g}$ is regular and hence an integral domain. Since $G$ is locally noetherian
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and connected, the claim follows.
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\end{proof}
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\begin{definition}
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An \emph{abelian variety} over $k$ is a connected, geometrically reduced
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and proper $k$-group scheme.
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\end{definition}
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\begin{bem}
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Abelian varieties are smooth and geometrically integral.
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\end{bem}
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\begin{bsp}
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Elliptic curves are abelian varieties of dimension $1$.
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\end{bsp}
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The goal is now to show that abelian varieties are commutative group schemes.
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\begin{lemma}
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Let $X$ be a proper, geometrically connected and geometrically reduced $k$-scheme and
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$Y$ an affine $k$-scheme. Then every morphism $X \xrightarrow{f} Y$ factors over a
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$k$-valued point of $Y$.
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\label{lemma:constant-of-proper-conn-irred-affine}
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\end{lemma}
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\begin{proof}
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By the Liouville theorem for schemes, the global
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sections of $\mathcal{O}_{X_{\bar k}}$ is $\bar k$. Since
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$k \to \bar k$ is flat, we obtain
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\[
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\Gamma(X, \mathcal{O}_X) \otimes_k \bar k
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\xlongrightarrow{\simeq} \Gamma(X_{\bar k}, \mathcal{O}_{X_{\bar k}})
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.\] Since $k \to \bar k$ is even faithfully flat, we obtain
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$\Gamma(X, \mathcal{O}_X) \simeq k$.
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Choose an embedding $Y \hookrightarrow \mathbb{A}_k^{(I)}$. Then a
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morphism $f\colon X \to Y$ is equivalent to a morphism
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$X \xrightarrow{f} Y \hookrightarrow \mathbb{A}_k^{(I)}$, which is equivalent
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to the datum of a family of $e_i \in \Gamma(X, \mathcal{O}_X)$ which
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corresponds to a morphism
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$\Spec k \xrightarrow{e} \mathbb{A}_k^{(I)}$. Thus by construction we obtain
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a factorisation
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\[
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\begin{tikzcd}
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X \arrow{r}{f} \arrow[dashed]{d} & Y \arrow{r} & \mathbb{A}^{(I)} \\
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\Spec k \arrow{rru}
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\end{tikzcd}
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\] where the dashed arrow is induced from the isomorphism $\Gamma(X, \mathcal{O}_X) \simeq k$.
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\end{proof}
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\begin{lemma}[Rigidity]
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Let $X$ be a geometrically reduced, geometrically connected and proper $k$-scheme
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with $X(k) \neq \emptyset$. Let further $Y$ be an integral scheme over $k$, $Z$
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be a separated $k$-scheme and $f\colon X \times_k Y \to Z$ a morphism such that
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there exists $y \in Y(k)$ such that
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$f|_{X_{y}}$ factors via a $k$-point $z \in Z(k)$. Then
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$f$ factors via $\mathrm{pr}_2$.
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\label{lemma:rigidity}
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\end{lemma}
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\begin{proof}
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Consider the composition
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\[
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g\colon X \times_k Y \xrightarrow{pr_2} Y \simeq \Spec k \times_k Y
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\xrightarrow{(x_0, \mathrm{id})} X \times_k Y \xrightarrow{f} Z
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\] where $x_0$ is an arbitrarily chosen $k$-rational point of $X$.
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It remains to show that $f = g$. Choose an open affine
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neighbourhood $z \in U \subseteq Z$. Then
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$X_y = \mathrm{pr}_2^{-1}(y) \subseteq f^{-1}(U)$. Since
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$X$ is proper, $\mathrm{pr}_2$ is a closed map. Thus there
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exists a $y \in V \subseteq Y$ open
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with $\mathrm{pr}_2^{-1}(V) \subseteq f^{-1}(U)$. For
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any $y' \in V$, we obtain
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\[
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\begin{tikzcd}
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X \times_k Y \arrow{r}{f} & Z \\
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X_{y'} \arrow[dashed, swap]{d}{\alpha(y')}
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\arrow[hookrightarrow]{u} \arrow[dashed]{r} & U \arrow[hookrightarrow]{u} \\
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U \times_k \kappa(y') \arrow{ur}
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\end{tikzcd}
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.\] By \ref{lemma:constant-of-proper-conn-irred-affine}, the morphism
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$\alpha(y')$ factors over a $\kappa(y')$-valued point. Thus
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$f$ and $g$ agree on the dense open subset $X \times_k V$. By reduced-to-separated,
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the result follows.
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\end{proof}
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\begin{korollar}
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Let $A$ and $B$ be abelian varieties over $k$
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and $f$ a morphism of $k$-schemes $A \to B$. If under the induced
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map $f(k)\colon A(k) \to B(k)$ the identity $e_A$ is mapped to $e_B$.
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\label{cor:av-group-homs}
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\end{korollar}
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\begin{proof}
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Consider the composition
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\[
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g\colon A \times_k A \xrightarrow{(f \circ m_A) \times (i_B \circ m_A \circ (f \times f))}
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B \times_k B
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\xrightarrow{m_B}
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B
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.\] It remains to show that the image of $g$ is precisely $\{e_B\} $. By
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assumption $f(e_A) = e_B$ and thus
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\[
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g(\{e_A\} \times_k A) = \{ e_B\} = g(A \times_k \{e_A\})
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.\] By repeated application of \ref{lemma:rigidity}, $g$ factors
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via $\mathrm{pr}_1$ and $\mathrm{pr}_2$. Thus $g$ is constant and $e_B$ is in the image.
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\end{proof}
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\begin{korollar}
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Every abelian variety is commutative.
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\end{korollar}
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\begin{proof}
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Apply \ref{cor:av-group-homs} on $i\colon A \to A$.
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\end{proof}
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\end{document}
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