An R package to analyze the parliamentary records of the 19th legislative period of the Bundestag, the German parliament.
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  1. ---
  2. title: "General questions"
  3. output: rmarkdown::html_vignette
  4. vignette: >
  5. %\VignetteIndexEntry{General questions}
  6. %\VignetteEngine{knitr::rmarkdown}
  7. %\VignetteEncoding{UTF-8}
  8. ---
  9. ```{r, include = FALSE}
  10. knitr::opts_chunk$set(
  11. collapse = TRUE,
  12. comment = "#>"
  13. )
  14. ```
  15. ```{r setup}
  16. library(hateimparlament)
  17. library(dplyr)
  18. library(ggplot2)
  19. library(stringr)
  20. library(tidyr)
  21. ```
  22. ## Preparation of data
  23. First, you need to download all records of the current legislative period.
  24. ```r
  25. fetch_all("../inst/records/") # path to directory where records should be stored
  26. ```
  27. Second, those `.xml` files, need to be parsed into `R` `tibbles`. This is accomplished by:
  28. ```r
  29. read_all("../inst/records/") %>% repair() -> res
  30. ```
  31. We also used `repair` to fix a bunch of formatting issues in the records.
  32. For development purposes, we load the tables from csv files.
  33. ```{r}
  34. res <- read_from_csv('../inst/csv/')
  35. ```
  36. ## Analysis
  37. Now we can start analysing our parsed dataset:
  38. ### Which party gives the most talks?
  39. ```{r, fig.width=7}
  40. join_speaker(res$speeches, res) %>%
  41. group_by(fraction) %>%
  42. summarize(n = n()) %>%
  43. arrange(n) %>%
  44. bar_plot_fractions(title="Number of speeches given by fraction",
  45. ylab="Number of speeches")
  46. ```
  47. Note that `NA` signifies speeches given by speakers who are not members of parliament.
  48. ### Who gives the most speeches?
  49. ```{r}
  50. res$speeches %>%
  51. group_by(speaker) %>%
  52. summarize(n = n()) %>%
  53. arrange(-n) %>%
  54. left_join(res$speaker, by=c("speaker" = "id")) %>%
  55. head(10)
  56. ```
  57. ### Who talks the longest?
  58. Calculate the average character length of talks given by speakers:
  59. ```{r}
  60. res$talks %>%
  61. mutate(content_len = str_length(content)) %>%
  62. group_by(speaker) %>%
  63. summarize(avg_content_len = mean(content_len)) %>%
  64. arrange(-avg_content_len) %>%
  65. left_join(res$speaker, by=c("speaker" = "id")) %>%
  66. head(10)
  67. ```