update la7
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@@ -48,7 +48,7 @@
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\newtheorem{bsp}[satz]{Beispiel}
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\newtheorem{bsp}[satz]{Beispiel}
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\newtheorem{bem}[satz]{Bemerkung}
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\newtheorem{bem}[satz]{Bemerkung}
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\newtheorem{aufgabe}[satz]{Aufgabe}
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\newtheorem{aufgabe}{Aufgabe}
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\newcommand{\N}{\mathbb{N}}
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\newcommand{\N}{\mathbb{N}}
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\newcommand{\R}{\mathbb{R}}
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\newcommand{\R}{\mathbb{R}}
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@@ -46,27 +46,27 @@
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Definiere:
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Definiere:
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\begin{align*}
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\begin{align*}
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&w_1 := \begin{cases}
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&w_1 := \begin{cases}
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1 & \exists k \in \N\colon n = 3k+1 \\
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1 & \exists k \in \N_0\colon n = 3k+1 \\
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0 & \exists k \in \N\colon n = 3k+2 \\
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0 & \exists k \in \N_0\colon n = 3k+2 \\
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-1 & \exists k \in \N\colon n = 3k
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-1 & \exists k \in \N_0\colon n = 3k
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\end{cases}, \qquad
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\end{cases}, \qquad
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w_2 \colon= \begin{cases}
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w_2 \colon= \begin{cases}
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0 & \exists k \in \N\colon n = 3k+1 \\
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0 & \exists k \in \N_0\colon n = 3k+1 \\
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1 & \exists k \in \N\colon n = 3k+2 \\
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1 & \exists k \in \N_0\colon n = 3k+2 \\
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-1 & \exists k \in \N\colon n = 3k
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-1 & \exists k \in \N_0\colon n = 3k
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\end{cases}
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\end{cases}
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.\end{align*}
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.\end{align*}
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Zz.: $w_1, w_2 \in W$. Sei $n \in \N$ beliebig.
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Zz.: $w_1, w_2 \in W$. Sei $n \in \N$ beliebig.
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Falls $\exists k \in \N\colon n = 3k+1$, dann $n + 1 = 3k+2$ und $n + 2 = 3(k+1)$.
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Falls $\exists k \in \N_0\colon n = 3k+1$, dann $n + 1 = 3k+2$ und $n + 2 = 3(k+1)$.
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\begin{align*}
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\begin{align*}
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w_1(n) + w_1(n+1) + w_1(n+2) &= 1 + 0 - 1 = 0
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w_1(n) + w_1(n+1) + w_1(n+2) &= 1 + 0 - 1 = 0
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\intertext{und}
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\intertext{und}
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w_2(n) + w_2(n+1) + w_2(n+2) &= 0 + 1 - 1 = 0
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w_2(n) + w_2(n+1) + w_2(n+2) &= 0 + 1 - 1 = 0
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.\end{align*}
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.\end{align*}
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Fälle $\exists k \in \N\colon n = 3k+2$ bzw. $n = 3k$ folgen analog.
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Fälle $\exists k \in \N_0\colon n = 3k+2$ bzw. $n = 3k$ folgen analog.
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Zz.: $\{w_1, w_2\} $ ist Erzeugendensystem. Sei $f \in W$ beliebig.
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Zz.: $\{w_1, w_2\} $ ist Erzeugendensystem. Sei $f \in W$ beliebig.
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Wähle $a_1 := f(1)$ und $a_2 := f(2)$. Damit gilt:
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Wähle $a_1 := f(1)$ und $a_2 := f(2)$. Damit gilt:
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