fix error in la3 and update lectures
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@@ -143,8 +143,8 @@
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}%
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}%
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% integral d sign
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% integral d sign
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\makeatletter \renewcommand\d[1]{\ensuremath{%
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\makeatletter \renewcommand\d[2][]{\ensuremath{%
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\;\mathrm{d}#1\@ifnextchar\d{\!}{}}}
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\,\mathrm{d}^{#1}#2\@ifnextchar^{}{\@ifnextchar\d{}{\,}}}}
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\makeatother
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\makeatother
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% contradiction
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% contradiction
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+1
-1
Submodule sose2020/ana/lectures updated: 52281b1525...7035188af9
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@@ -251,16 +251,16 @@
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\colops
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\colops
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\add[-(-3 + t)]{1}{2}
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\add[-(-3 + t)]{1}{2}
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\rowops
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\rowops
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\add[t+t-t^2]{1}{2}
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\add[1+t-t^2]{1}{2}
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\end{gmatrix} \\
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\end{gmatrix} \\
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&\rightsquigarrow
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&\rightsquigarrow
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\begin{gmatrix}[p] 1 & 0 & 0 \\
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\begin{gmatrix}[p] 1 & 0 & 0 \\
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0 & 1 & 0 \\
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0 & 1 & 0 \\
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0 & 0 & 8 + t - 4t^2 + t^3
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0 & 0 & 2 - 5t + 4t^2 - t^3
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\end{gmatrix}
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\end{gmatrix}
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.\end{align*}
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.\end{align*}
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Damit folgen die Elementarteiler $1$, $1$ und $8 + t - 4t^2 + t^3$. Für die Fittingideale gilt
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Damit folgen die Elementarteiler $1$, $1$ und $2 - 5t + 4t^2 - t^3$. Für die Fittingideale gilt
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$\text{Fit}_1(B) = (1)$, $\text{Fit}_2(B) = (1)$ und $\text{Fit}_3(B) = (8 + t - 4t^2 + t^{3})$.
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$\text{Fit}_1(B) = (1)$, $\text{Fit}_2(B) = (1)$ und $\text{Fit}_3(B) = (2 - 5t + 4t^2 - t^{3})$.
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\end{enumerate}
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\end{enumerate}
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\end{aufgabe}
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\end{aufgabe}
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