add lecture 2
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\tableofcontents
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\tableofcontents
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\input{lec01}
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\input{lec01}
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\input{lec02}
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\bibliographystyle{alpha}
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\bibliography{refs}
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\end{document}
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\end{document}
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\documentclass{lecture}
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\begin{document}
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\section{Useful statements on schemes}
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Let $k$ be a field.
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\begin{definition}
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Let $\mathcal{P}$ be a property of schemes over fields. For
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a $k$-scheme $X$ we say
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\emph{$X$ is geometrically} $\mathcal{P}$ if for all field extensions
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$K / k$ the base change $X_K \to \mathrm{Spec}\ K$ is $\mathcal{P}$.
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\end{definition}
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\begin{bsp}
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The $\R$-scheme $X = \mathrm{Spec}\left( \R[x]/(x^2 + 1) \right) $
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is irreducible but not geometrically irreducible.
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\end{bsp}
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\begin{satz}[]
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For a $k$-scheme $X$ the following are equvialent:
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\begin{enumerate}[(i)]
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\item $X$ is geometrically reduced
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\item for every reduced $k$-scheme $Y$, the fibre product $X \times_k Y$ is reduced.
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\item $X$ is reduced and for every generic point $\eta \in X$ of an
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irreducible component of $X$, the field extension
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$\kappa(\eta) / k$ is separable.
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\item There exists a perfect field $\Omega$ and an extension $\Omega / k$ such that
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$X_{\Omega}$ is reduced.
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\item For all finite and purely inseparable field extensions $K / k$,
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the base change $X_K$ is reduced.
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\end{enumerate}
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\label{prop:char-geom-red}
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\end{satz}
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\begin{proof}
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Reducedness is a local property, so without loss of generality $X = \mathrm{Spec}\ A$. Moreover
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we may assume that $X$ itself is reduced. Let
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$\left\{ \eta_i \right\}_{i \in I}$ be the set of generic points of irreducible components
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of $X$. Then we obtain an inclusion
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\[
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A \hookrightarrow \prod_{i \in I} \underbrace{\kappa(\eta_i)}_{= S_i^{-1} A}
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.\] We claim that for any field extension $L / k$ the ring $A \otimes_k L$ is reduced
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if and only if for all $i \in I$ the ring $\kappa(\eta_i) \otimes_k L$ is reduced.
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\begin{proof}[proof of the claim]
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$(\Rightarrow)$: follows since forming the nilradical commutes with localisations.
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$(\Leftarrow)$: We have
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\[
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A \otimes_k L \hookrightarrow \left( \prod_{i \in I}^{} \kappa(\eta_i) \right)
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\otimes_k L
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\hookrightarrow \prod_{i \in I}^{} \kappa(\eta_i) \otimes_k L
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.\]
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\end{proof}
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The claim immediatly implies the equivalence of (iii), (iv), (v) and (1). Since
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(ii) trivially implies (i). It remains to show that (iii) implies (2).
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Without loss of generality we may take $Y = \mathrm{Spec}\ B$
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and set $\{\lambda_j\}_{j \in J}$ to be the generic points of $Y$. Then we obtain
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\[
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A \otimes_k B \hookrightarrow
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A\otimes_k \left( \prod_{j \in J} \kappa(\lambda_j) \right)
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\hookrightarrow
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\left( \prod_{i \in I} \kappa(\eta_i) \right)
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\otimes_k
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\left( \prod_{j \in J} \kappa(\lambda_j) \right)
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\hookrightarrow
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\prod_{i,j}^{} \underbrace{\kappa(\eta_i) \otimes_k \kappa(\eta_j) }_{\text{reduced}}
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.\]
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\end{proof}
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\begin{korollar}
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If $k$ is perfect, then
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reduced and geometrically reduced are equivalent.
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\end{korollar}
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\begin{bem}[]
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The statements in \ref{prop:char-geom-red} also hold when
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\emph{reduced} is replaced by \emph{irreducible} or \emph{integral}.
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\end{bem}
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\begin{satz}
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Let $f\colon X \to Y$ be a morphism of schemes that is locally of finite presentation.
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Then $f$ is open if and only if
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for every point $x \in X$ and every point $y' \in Y$ with
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$y = f(x) \in \overline{\{y'\} }$ there exists
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$x' \in X$ with $x \in \overline{\{x'\} }$ such that $f(x') = y'$.
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\label{prop:open-stab-gener}
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\end{satz}
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\begin{proof}
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Assume $X = \mathrm{Spec}\ B$ and $Y = \mathrm{Spec}\ A$.
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$(\Rightarrow)$: Then set
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\[
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Z \coloneqq \mathrm{Spec}\ \mathcal{O}_{X,x}
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\cap \bigcap_{t \in B \setminus \mathfrak{p}_x} D(t)
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.\] Since $f$ is open, $y' \in f(D(t))$ for all $t \in B \setminus \mathfrak{p}_x$.
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Set $f_t \coloneqq f|_{D(t)}$. Then $f_t ^{-1}(y') \neq \emptyset$. For sake
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of contradiction suppose that $y' \not\in f(Z)$. Then set
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$g\colon \mathrm{Spec}\ \mathcal{O}_{X,x} \to X \xrightarrow{f} Y$.
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Therefore
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\[
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\emptyset = g^{-1}(y') = \mathrm{Spec}\ \left( \mathcal{O}_{X,x} \otimes_A \kappa(y') \right)
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.\] Thus
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\[
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0 = \mathcal{O}_{X,x} \otimes_A \kappa(y')
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= \operatorname{colim}_{t \in B \setminus \mathfrak{p}_x}
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\underbrace{B_t \otimes_A \kappa(y')}_{\neq 0}
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\] which is a contradiction.
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$(\Leftarrow)$:
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Show $f(X) \subseteq Y$ is open. By Chevalley's theorem (\cite{gw}, 10.70),
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the image $f(X)$ is constructible. In the noetherian case
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use that open is equivalent to constructible and stable under generalizations
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(\cite{gw}, 10.17). In the general case write $A$ as a colimit of noetherian rings and
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conclude by careful general nonsense.
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\end{proof}
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\begin{lemma}
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Let $f\colon X \to Y$ be flat, $x \in X$, $y = f(x)$, $y' \in Y$ a
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generalization of $y$. Then there exists a generalization $x'$ of $x$ such that
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$f(x') = y'$.
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\label{lemma:flat-stable-gener}
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\end{lemma}
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\begin{proof}
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Set $A = \mathcal{O}_{Y,y}$, $B = \mathcal{O}_{X,x}$ and
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$\varphi\colon A \to B$. Since $y \in \text{im}(f)$
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we have $\mathfrak{m}_yB \neq B$ and
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$B$ is faithfully flat $A$-module (since $\varphi$ is local and flat). Thus
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\[
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0 \neq B \otimes_A \kappa(y')
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,\] i.e. $f^{-1}(y') \cap \mathrm{Spec}\ B \neq \emptyset$.
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\end{proof}
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\begin{korollar}
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Let $f\colon X \to Y$ be flat and locally of finite presentation. Then $f$ is universally
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open.
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\end{korollar}
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\begin{proof}
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From \ref{prop:open-stab-gener} and \ref{lemma:flat-stable-gener} follows
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that flat and locally of finite presentation implies open. Since the former
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two properties are stable under base change, the result follows.
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\end{proof}
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\begin{korollar}
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Let $f\colon X \to S$ be locally of finite presentation. If
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$|S|$ is discrete, then every morphism $X \to S$ is universally open.
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\end{korollar}
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\begin{definition}[]
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Let $f\colon X \to Y$. We say
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\begin{enumerate}[(i)]
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\item $f$ is \emph{flat in $x \in X$} if
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$f_x^{\#}\colon \mathcal{O}_{Y,f(x)} \to \mathcal{O}_{X,x}$ is flat.
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\item $f$ is \emph{flat} if
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$f$ is flat in every point.
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\end{enumerate}
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\end{definition}
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\begin{bsp}[]
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\begin{enumerate}[(1)]
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\item $X \to \mathrm{Spec}\ k$ is flat.
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\item $\mathbb{A}_{Y}^{n} \to Y$ and
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$\mathbb{P}_{Y}^{n} \to Y$ are flat.
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\item Let $f\colon Z \hookrightarrow Y$ be a closed immersion. Then
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$f$ is flat and locally of finite presentation if and only if $f$ is an open immersion.
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\end{enumerate}
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\end{bsp}
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\begin{satz}
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The following holds
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\begin{enumerate}[(i)]
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\item $\mathrm{Spec}\ B \to \mathrm{Spec}\ A$ is flat if and only if $A \to B$ is flat.
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\item Flatness is stable under base change and composition.
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\item Flatness is local on the source and the target.
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\item Open immersions are flat.
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\item A morphism $f\colon X \to Y$ is flat if and only if
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for every $y \in Y$ the canonical morphism
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\[
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X \times_Y \mathrm{Spec}(\mathcal{O}_{X,y})
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\to \mathrm{Spec}(\mathcal{O}_{Y,y})
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\] is flat.
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\end{enumerate}
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\end{satz}
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\begin{definition}
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A morphism $f\colon X \to Y$ is called \emph{faithfully flat} if
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$f$ is flat and surjective.
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\end{definition}
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\begin{bsp}[]
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$\mathrm{Spec}\ \overline{k} \to \mathrm{Spec}\ k$ is faithfully flat.
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\end{bsp}
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\begin{lemma}
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Let $\mathcal{C}$ be a category with equalizers, $F\colon \mathcal{C} \to \mathcal{D}$ a
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conservative (i.e. reflects isomorphisms) functor that commutes with equalizers. Then
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$F$ is faithful.
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\label{lemma:cons-eq-faithful}
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\end{lemma}
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\begin{proof}
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Left as an exercise to the reader.
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\end{proof}
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\begin{satz}
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Is $f\colon X \to Y$ faithfully flat, then
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$f^{*}\colon \mathrm{QCoh}(Y) \to \mathrm{QCoh}(X)$ faithful.
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\label{prop:faithfully-flat-faithful-pullback}
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\end{satz}
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\begin{proof}
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Can be deduced from \ref{lemma:cons-eq-faithful}. The details are left to the reader.
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\end{proof}
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\begin{bem}[Faithfully flat descent]
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The statement from \ref{prop:faithfully-flat-faithful-pullback} can be
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- from a carefully selected viewpoint - viewn as the statement
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that the functor $X \mapsto \mathrm{QCoh}(X)$ satisfies the sheaf condition
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for faithfully flat and quasicompact morphisms, i.e. that the diagram
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\[
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\begin{tikzcd}
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\mathrm{QCoh}(Y)
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\arrow{r}{f^{*}}
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& \mathrm{QCoh}(X)
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\arrow[yshift=2pt]{r}{\text{pr}_1^{*}}
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\arrow[swap, yshift=-2pt]{r}{\text{pr}_2^{*}}
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&\mathrm{QCoh}(X \times_Y X)
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\arrow[yshift=4pt]{r}
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\arrow[yshift=0pt]{r}
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\arrow[yshift=-4pt]{r}
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&
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\underbrace{\mathrm{QCoh}(X \times_Y X \times_Y X)}_{\text{corresponds to the cocycle condition}}
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\end{tikzcd}
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\] is a limit diagram.
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\end{bem}
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\begin{satz}[\cite{gw}, 14.53]
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Let $f\colon X \to Y$ be a $S$-morphism and
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$g\colon S' \to S$ faithfully flat and quasicompact.
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Denote by $f' = f \times_S S'$. If $f'$ is
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\begin{enumerate}[(i)]
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\item (locally) of finite type or (locally) of finite presentation,
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\item isomorphism / monomorphism,
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\item open / closed / quasicompact immersion,
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\item proper / affine / finite,
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\end{enumerate}
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then $f$ has the same property.
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\end{satz}
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\end{document}
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@book {gw,
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AUTHOR = {G\"{o}rtz, Ulrich and Wedhorn, Torsten},
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TITLE = {Algebraic geometry {I}},
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SERIES = {Advanced Lectures in Mathematics},
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NOTE = {Schemes with examples and exercises},
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PUBLISHER = {Vieweg + Teubner, Wiesbaden},
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YEAR = {2010},
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PAGES = {viii+615},
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ISBN = {978-3-8348-0676-5},
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MRCLASS = {14-01},
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MRNUMBER = {2675155},
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MRREVIEWER = {C\'{\i}cero\ Carvalho},
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DOI = {10.1007/978-3-8348-9722-0},
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URL = {https://doi.org/10.1007/978-3-8348-9722-0},
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}
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